查找array 中某个元素的位置

index = np.where(A==a)[0]

查找list 中某个元素的位置

A.index(a)

注意： array的np.where只能返回某一个元素的数值； list可以实现一组点列中删选出第一个出现该点（三维坐标）的位置值

将list中的元素转为str类型

方法一：

>>> L = [1,2,3,4,5]
>>> map(str, L)
['1', '2', '3', '4', '5']

a = [1,2,3]
b = [ str(i) for i in a ]

查找某一个三维点在一组点列中的位置，即查找重复点的位置，取三维坐标值的两位有效精度

v=[[-3.68151387e-03, -4.20966751e-01,  1.00000000e+00],
       [-1.64405958e-01, -1.22046324e+00,  1.00000000e+00],
       [-5.42200556e-01, -9.09887918e-01,  1.00000000e+00],
       [-3.39455904e-01, -8.54805218e-01,  1.00000000e+00],
       [ 5.37373562e-01, -9.11539726e-01,  1.00000000e+00],
       [ 3.32122909e-01, -8.56312500e-01,  1.00000000e+00],
       [ 1.58178608e-01, -1.21939329e+00,  1.00000000e+00],
       [-1.10745951e+00, -3.30272672e+00,  1.00000000e+00],
       [ 1.09744188e+00, -3.30336923e+00,  1.00000000e+00],
       [ 1.93152989e+00, -2.72303064e+00,  1.00000000e+00],
       [ 2.16004036e+00,  6.98467630e-01,  1.00000000e+00],
       [-1.14289140e-03,  1.86489518e+00,  1.00000000e+00],
       [ 2.16004036e+00,  6.98467630e-01,  1.00000000e+00],
       [-2.17124803e+00,  6.93662998e-01,  1.00000000e+00],
       [-1.14289140e-03,  1.86489518e+00,  1.00000000e+00],
       [-1.94018776e+00, -2.71842407e+00,  1.00000000e+00],
       [-2.17124803e+00,  6.93662998e-01,  1.00000000e+00],
       [ 1.93152989e+00, -2.72303064e+00,  1.00000000e+00],
       [ 1.09744188e+00, -3.30336923e+00,  1.00000000e+00],
       [-1.10745951e+00, -3.30272672e+00,  1.00000000e+00],
       [-1.94018776e+00, -2.71842407e+00,  1.00000000e+00]]
 
 [[round(a,2) for a in row] for row in v]
Out[72]: 
[[-0.0, -0.42, 1.0],
 [-0.16, -1.22, 1.0],
 [-0.54, -0.91, 1.0],
 [-0.34, -0.85, 1.0],
 [0.54, -0.91, 1.0],
 [0.33, -0.86, 1.0],
 [0.16, -1.22, 1.0],
 [-1.11, -3.3, 1.0],
 [1.1, -3.3, 1.0],
 [1.93, -2.72, 1.0],
 [2.16, 0.7, 1.0],
 [-0.0, 1.86, 1.0],
 [2.16, 0.7, 1.0],
 [-2.17, 0.69, 1.0],
 [-0.0, 1.86, 1.0],
 [-1.94, -2.72, 1.0],
 [-2.17, 0.69, 1.0],
 [1.93, -2.72, 1.0],
 [1.1, -3.3, 1.0],
 [-1.11, -3.3, 1.0],
 [-1.94, -2.72, 1.0]]
 
 b=[[round(a,2) for a in row] for row in v]

b.index([-1.94, -2.72, 1.0])
Out[74]: 15

b.index([1.93, -2.72, 1.0])
Out[75]: 9